SOLUTION: Jim can run 5 miles per hour on a level ground on a still day. One windy day, he runs 11 miles with the wind, and in the same amount of time runs 6 miles against the wind. what is

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Question 378755: Jim can run 5 miles per hour on a level ground on a still day. One windy day, he runs 11 miles with the wind, and in the same amount of time runs 6 miles against the wind. what is the rate of the wind?
Found 2 solutions by scott8148, mananth:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
t = d / r ___ the times are the same (equal)

11 / (5+w) = 6 / (5-w)

"cross" multiplying ___ 55 - 11w = 30 + 6w

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
jim speed = 5 mph
let speed of wind be w mph
..
against wind speed = 5-w
with wind speed = 5+w
...
distance against wind = 6 miles
distance with wind = 11 miles
..
t=d/r
time against = time with
6%2F%285-w%29=11%2F%285%2Bw%29
...
cross multiply
6(5+w)=11(5-w)
30+6w=55-11w
6w+11w=55-30
17w=25
/17
w=25/17
w= 1.47 mph the speed of wind
...
m.ananth@hotmail.ca