SOLUTION: Two buses leave a station at the same time, traveling in opposite directions. The rate of the slower bus is 15mph less than the rate of the faster bus. After 4 hours, they are 492
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Question 356825: Two buses leave a station at the same time, traveling in opposite directions. The rate of the slower bus is 15mph less than the rate of the faster bus. After 4 hours, they are 492 miles apart. What is the rate of the slower bus? Found 2 solutions by ankor@dixie-net.com, rfer:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Two buses leave a station at the same time, traveling in opposite directions.
The rate of the slower bus is 15mph less than the rate of the faster bus.
After 4 hours, they are 492 miles apart.
What is the rate of the slower bus?
:
Let s = speed of the slower bus
then
(s+15) = speed of the faster bus
:
When they travel in opposite directions, the distances are added
Write a distance equation. Dist = time * speed
:
4s + 4(s+15) = 492
4s + 4s + 60 = 492
8s = 492 - 60
8s = 432
s =
s = 54 mph is the rate of the slower bus
:
:
Check this by finding the total distances (54+15=69mph is the faster bus)
4(69) = 276
4(54) = 216
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total: 492
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