Question 331380: 1. Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
I can't seem to start it...not sure where to begin! Help please...
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
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In 3 hours, the 1st cyclist is 18 miles ahead (3*6).
The 2nd cyclist gains on him at 4 mph (10 - 6).
18/4 = 2.25 hours
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There are other ways to do it, more math, more equations, more work.
I don't recommend them.
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