SOLUTION: A bicycle leaves town at 10 mph at 8 am. A car leaves town going the same direction at 11am going 50 mph. How many minutes after 11 am will it be when the car overtakes the bicycle

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Question 316538: A bicycle leaves town at 10 mph at 8 am. A car leaves town going the same direction at 11am going 50 mph. How many minutes after 11 am will it be when the car overtakes the bicycle?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
D=10T FOR THE BICYCLE.
D=50(T-3) FOR THE CAR.
10T=50(T-3)
10T=50T-150
10T-50T=-150
-40T=-150
T=-150/-40
T=15/4=3.75 TRAVEL TIME FOR THE BICYCLE.
3.75-3=.75 TRAVEL TIME FOR THE CAR.
PROOF:
10*3.75=50*.75
37.5=37.5