SOLUTION: Please help with this question.
A water rocket is launched upward with an initial velocity of 48 ft/sec. It's height h, in ft after t seconds is given by h=48t-16t^2. After how ma
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A water rocket is launched upward with an initial velocity of 48 ft/sec. It's height h, in ft after t seconds is given by h=48t-16t^2. After how ma
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Question 314421: Please help with this question.
A water rocket is launched upward with an initial velocity of 48 ft/sec. It's height h, in ft after t seconds is given by h=48t-16t^2. After how many seconds will the rocket hit the ground? Please show all work necessary to arrive to the solution. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! The rocket is on the ground when .
Two solutions: , The rocket hasn't left yet.
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The rocket will hit the ground in 3 seconds.
