SOLUTION: Two small planes start from the same point and fly in opposite directions. The first plane is flying 25 miles per hour slower than the second plane. In 2 hours, the planes are 470

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Question 309870: Two small planes start from the same point and fly in opposite directions. The first plane is flying
25 miles per hour slower than the second plane. In 2 hours, the planes are 470 miles apart. Find the rate of each plane

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Think of 1 plane as stationary and the other as moving away from it
at the sum of their speeds
Let s = the speed of the faster plane
s+-+25 = the speed of the slower plane
The sum of their speeds is s+%2B+s+-+25+=+2s+-+25
In 2 hrs:
470+=+%282s+-+25%29%2A2
470+=+4s+-+50
4s+=+520
s+=+130
s+-+25+=+105
The 1st planes flies at 105 mi/hr
The 2nd plane flies at 130 mi/hr
check:
1st plane:
d%5B1%5D+=+105%2A2
d%5B1%5D+=+210 mi
2nd plane:
d%5B2%5D+=+130%2A2
d%5B2%5D+=+260
d%5B1%5D+%2B+d%5B2%5D+=+210+%2B+260
d%5B1%5D+%2B+d%5B2%5D+=+470
OK