SOLUTION: Two cars leave an intersection. One car travels east; the other north. When the car traveling east had gone 15 miles, the distance between the cars was 5 miles more than the distan

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Question 301604: Two cars leave an intersection. One car travels east; the other north. When the car traveling east had gone 15 miles, the distance between the cars was 5 miles more than the distance traveled by the car heading north. How far had the northbound car traveled?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The 2 cars and their starting point form a right triangle
One leg is 15 mi
Call the north leg x
Then the distance between the cars is 5+%2B+x
x%5E2+%2B+15%5E2+=+%28x%2B5%29%5E2
x%5E2+%2B+225+=+x%5E2+%2B+10x+%2B+25
10x+=+225+-+25
10x+=+200
x+=+20
The northbound car had gone 20 mi
check:
x%5E2+%2B+15%5E2+=+%28x%2B5%29%5E2
20%5E2+%2B+15%5E2+=+%2820%2B5%29%5E2
400+%2B+225+=+625
625+=+625
OK