SOLUTION: The speed of a passenger train is 10mph faster than the speed of a freight train. The passenger train travels 290 miles in the same time it takes the freight train to travel 240 mi

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: The speed of a passenger train is 10mph faster than the speed of a freight train. The passenger train travels 290 miles in the same time it takes the freight train to travel 240 mi      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 298907: The speed of a passenger train is 10mph faster than the speed of a freight train. The passenger train travels 290 miles in the same time it takes the freight train to travel 240 miles. Find the speed of each train. A) Passenger train_? B) Freight train_ (mph)?
Found 2 solutions by checkley77, J.A.Romero:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
290=(R+10)T PASSENGER TRAIN
T=290/(R+10)
240=RT FREIGHT TRAIN
T=240/R
290/(R+10)=240/R
290R=240(R+10)
290R=240R+2400
290R-240R=2400
50R=2400
R=2400/50
R=48 MPH FOR THE FREIGHT TRAIN.
48+10=58 MPH FOR THE PASSENGER TRAIN.
240=48T
T=240/48
T=5 HOURS IS THE TIME OF THE TRIP.
PROOF:
290=58*5
290=290

Answer by J.A.Romero(2) About Me  (Show Source):
You can put this solution on YOUR website!
freighttrain=r:(mph)
passengertrain=r%2B10:(mph)
distance=rate*time, D=RT
passengertrain=290miles=%28dist%2Ft%29%2B10%2At
d=rt;290=R%2B10%2AT;T=290%2FR%2B10
freighttrain=240miles=%28dist%2Ft%29%28t%29
d=rt;240=R%2AT;T=240%2FR
290%2Fr%2B10=240%2Fr
r%28r%2B10%29%2A240%2Fr=r%28r%2B10%29%2A290%2Fr%2B10
%28r%2B10%29%2A240=290%28r%29
240r%2B2%2C400=290r
240r%2B2%2C400-240r=290r-240r;2%2C400=50r
freighttrain=r:(mph)
passengertrain=r%2B10:(mph)
R=48
R=48%2B10
Freighttrain=48%3A%28mph%29
Passengertrain=58%3A%28mph%29