SOLUTION: Bob travels on a train at 80 mph with a 30 minute layover halfway through the 156 mile trip at 8:00a.m. or by car traveling 55 mph at 8:00a.m. traveling 156 miles. Which method o
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Question 288624: Bob travels on a train at 80 mph with a 30 minute layover halfway through the 156 mile trip at 8:00a.m. or by car traveling 55 mph at 8:00a.m. traveling 156 miles. Which method of transportation train or car allows Bob to arrive sooner at his destination? Found 2 solutions by ankor@dixie-net.com, richwmiller:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Bob travels on a train at 80 mph with a 30 minute layover halfway through
the 156 mile trip at 8:00a.m. or by car traveling 55 mph at 8:00a.m. traveling 156 miles.
Which method of transportation train or car allows Bob to arrive sooner at his destination?
:
Write a time equation for each; time = dist/speed
:
Train: + .5 = 2.45 hrs
Car: = 2.84 hrs
:
Obviously, the train wins!
You can put this solution on YOUR website! There really isn't enough info to decide the real answer.
Where is the car? Where is the train station?
by train
80x=156
x=(156/80)*60+30
147 minutes
2 hr 27 minutes
by car
55*t=156
t=156/55)
(156/55)*60=170.1=2 hr 50 minutes
that is only a matter of 23 minutes
How far away is the train station? How would he get there?
