Question 263749: How far upstream can a motorboat travel at 8 mi/hr and still return downstream at 12 mi/hr in a total time of 4 hr?
Found 5 solutions by mananth, jsmallt9, ikleyn, josgarithmetic, MathTherapy:Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! How far upstream can a motorboat travel at 8 mi/hr and still return downstream at 12 mi/hr in a total time of 4 hr?
let the time taken upstream be x
the down stream time will be 4-x hrs.
speed upstream = 8mph
distance upstream = 8*x
distance down stream = 12*(4-x)
8x= 48-12x
16x=48
x=3 hour---------------------------------- 24 miles
down stream time = 1hour
You can put this solution on YOUR website! There is an error in a solution provided by another tutor. The other solution is correct up to
8x = 48 - 12x
Next we add 12x to each side:
20x = 48 (NOT 16x)
Dividing by 20 we get:
x = 48/20 = 12/5
Since x is the amount of time spent traveling upstream it is not the answer to the question. How far you can travel upstream is miles.
You can put this solution on YOUR website! .
How far upstream can a motorboat travel at 8 mi/hr and still return downstream at 12 mi/hr in a total time of 4 hr?
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The solution in the post by @mananth is INCORRECT due to arithmetic error.
His answer "3 hours upstream and 1 hour downstream" does not work, as everybody can check manually.
I came to bring a correct solution.
let the time taken upstream be x
the down stream time will be 4-x hrs.
speed upstream = 8 mph
distance upstream = 8*x
distance downstream = 12*(4-x)
8x = 48-12x
20x = 48
x = 48/20 = 2.4 hours = 2 hours and 24 minutes ---------------------------------- 24 miles
downstream time = 4 hours - 2.4 hours = 1.6 hours = 1 hour and 36 minutes.
The one way distance is 2.4 hours upstream * 8 mph = 19.2 miles.
How far upstream can a motorboat travel at 8 mi/hr and still return downstream at 12 mi/hr in a total time of 4 hr?
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Let distance, back and forth, be D
Then time taken to travel upstream, is
Also, time taken to travel downstream, is
We then get the following TOTAL-TIME equation:
3D + 2D = 96 ---- Multiplying by LCD, 24
5D = 96
Distance, back and forth, or