SOLUTION: To measure the speed of the jet stream, a weather plane left its base at noon and flew 800km directly against the stream with an air speed of 750 km/h. It then returned directly to

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Question 26024: To measure the speed of the jet stream, a weather plane left its base at noon and flew 800km directly against the stream with an air speed of 750 km/h. It then returned directly to its base, arriving at 2:24 P.M. What was the speed of the jet stream?
Thank you.
Found 2 solutions by Paul, stanbon:
Answer by Paul(988) (Show Source):
You can put this solution on YOUR website!
From noon till 2.24 its 2.4hours.
LEt the speed be x

750(x+2.4)=800x
750x+1800=800x
50x=1800
x=36

Hence, the speed of the jetstream is 36km/h.
Paul.

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Dividing 800km by 750km you get 1.066666 hrs. or 64 min.
The roundtrip, according to your posting, is 144 min.
So,the return trip took 80 min.
That would mean the return trip was against the wind.
Using d=rt you have this kind of data:
Flight out Data:
distance=800km; time=64min; rate=750km/hr
Flight back Data:
distance=800km; time=80min; rate=800km/80min=10km/min=600km/hr
Let plane speed be "p" and wind speed be "w"
Down wind you have: p+w=750km/hr
Against wind you have: p-w=600km/hr
Solve that system for P and w:
Adding the equations you get 2p=1350
p=675km/hr
Substituting you get p+w=750
675+w=750
w=75
The wind speed is 75km/hr
Cheers,
Stan H.