Question 255771: The safety director of an insurance company took samples at random from his minor accidents file and classified them according to the time the accident took place.
Number
Time of Accidents
8 - 9 am 6
9 - 10 am 6
10 - 11 am 20
11 - 12 am 8
1 - 2 pm 7
2 - 3 pm 8
3 - 4 pm 19
4 - 5 pm 6
Using the chi-square test and the .01 level of significance, determine whether or not the accidents are evenly distributed throughout the day.
a) What are the Null and Alternate Hypotheses?
b) What is the critical value?
c) What is the Decision Rule?
d) What is the test statistic?
e) What is the decision?
f) What does the decision infer?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The safety director of an insurance company took samples at random from his minor accidents file and classified them according to the time the accident took place.
Number
Time of Accidents
8 - 9 am 6
9 - 10 am 6
10 - 11 am 20
11 - 12 am 8
1 - 2 pm 7
2 - 3 pm 8
3 - 4 pm 19
4 - 5 pm 6
Using the chi-square test and the .01 level of significance, determine whether or not the accidents are evenly distributed throughout the day.
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There are 80 accidents in an 8-hr period.
If they were evenly distributed there would be 10 accidents in each hour.
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a) What are the Null and Alternate Hypotheses?
Ho: The proportions are equal
H1: At least one of the proportions is different.
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comment: I ran a Chi-Sq Goodness of Fit test on a TI-84 to get:
b) What is the critical value?
c) What is the Decision Rule?
d) What is the test statistic?
Chi-Sq = 19.54887...
The p-value = 0.006631...
e) What is the decision?
Since the p-value is less than 1% reject Ho at the 1% significance level.
f) What does the decision infer?
Accidents do not occur a the same rate during all hours of the work day.
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Cheers,
Stan H.
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