SOLUTION: Two jets are traveling toward each other and are 4000km apart. The rate of one jet is 100km/hr faster than the rate of the other. If the jets pass each other after 2.5 hours, wha
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Two jets are traveling toward each other and are 4000km apart. The rate of one jet is 100km/hr faster than the rate of the other. If the jets pass each other after 2.5 hours, wha
Log On
Question 251783: Two jets are traveling toward each other and are 4000km apart. The rate of one jet is 100km/hr faster than the rate of the other. If the jets pass each other after 2.5 hours, what is the rate of each jet? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Two jets are traveling toward each other and are 4000km apart. The rate of one jet is 100km/hr faster than the rate of the other. If the jets pass each other after 2.5 hours, what is the rate of each jet?
---
closing speed for the two jets is x + x+100 = 2x+100 km/h
------------
Equation:
time = distance/rate = 4000/(2x+100) hrs = 2.5 hrs
---
2000/(x+50) = 2.5
2.5x + 125 = 2000
2.5x = 1875
---
x = 750 km/h (speed of the slower jet)
x+100 = 850 km/h (speed of the faster jet)
=============================================
Cheers,
Stan H.
(