SOLUTION: a train leaves the station traveling west at 50 mph. One hour later a second train leaves the station traveling west on the same track traveling 65 mph. How many hours will it ta

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Question 243143: a train leaves the station traveling west at 50 mph. One hour later a second train leaves the station traveling west on the same track traveling 65 mph. How many hours will it take the second train to crash into the back of the first train
Found 2 solutions by checkley77, ankor@dixie-net.com:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
d=rt
d=50t
d=65(t-1)
50t=65(t-1)
50t=65t-65
50t-65t=-65
-15t=-65
t=-65/-15
t=13/3 or 4 1/3 hours after the first train leaves the station they will crash.
Proof:
50*13/3=65(13/3-1)
650/3=65(13/3-3/3)
650/3=65(10/3)
650/3=650/3

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
a train leaves the station traveling west at 50 mph.
One hour later a second train leaves the station traveling west on the same track traveling 65 mph.
How many hours will it take the second train to crash into the back of the first train
:
let t = travel time of the 2nd train
then
(t+1) = travel time of the 1st train
:
Essentially when the crash occurs, they will have traveled the same distance
write a distance equation dist = speed * time:
:
2nd train dist = 1st train dist
65t = 50(t+1)
65t = 50t + 50
65t - 50t = 50
15t = 50
t =
t = 3 hrs