SOLUTION: It has been estimated that 900 curies of a radioactive substance introduced at a point on the surface of the open sea would spread over an area of 24000km^2 in 30 days. Assuming th

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Question 222747: It has been estimated that 900 curies of a radioactive substance introduced at a point on the surface of the open sea would spread over an area of 24000km^2 in 30 days. Assuming that the area covered by the radioactive substance is a linear function of time t and is always circular in shape, express the radius r of the contamination as a function of t.
Do not simplify the number under the radical.
I worked it out and got r=((sqr(24000/pi))/(30))*t. It appears that this is not right though. Please explain what I am doing wrong.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
It has been estimated that 900 curies of a radioactive substance introduced at
a point on the surface of the open sea would spread over an area of 24000km^2 in 30 days.
:
Assuming that the area covered by the radioactive substance is a linear function of time t and
is always circular in shape, express the radius r of the contamination as a function of t.
:
Do not simplify the number under the radical.
:
I think what you got is pretty close, here's my take on this
:
Find the value of r when t = 30 days and area = 24000
:
pi%2A%2830r%29%5E2+=+24000
:
pi%2A900%2Ar%5E2+=+24000
:
r%5E2+=+24000%2F%28900%2Api%29
Reduce the fraction
r%5E2+=+80%2F%283%2Api%29
:
r+=+sqrt%2880%2F%283pi%29%29
:
:
r as a function of t
r+=+sqrt%2880%2F%283pi%29%29%2At
:
:
Check this find radius when t = 30 days
r+=+sqrt%2880%2F%283pi%29%29%2A30
r = 87.4 km
:
Find the area using this value for r
A = pi*87.4^2 = 24,000 sq/km; confirms our solution