SOLUTION: Two automobiles travel in opposite directions from the same starting point. If the speed of one is twice the speed of the other and they are 190.0 km apart at the end of 2.0 h, wh

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Question 218663: Two automobiles travel in opposite directions from the same starting point. If the speed of one is twice the speed of the other and they are 190.0 km apart at the end of 2.0 h, what is the speed of the slower car (in m/s)?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If vehicles are going in opposite directions, they can be treated
as 1 vehicle going at the combined speed of both
d+=+r%2At
190+=+%28r+%2B+2r%29%2A2
Note that I made things easy by calling rate r+%2B+2r
190+=+6r
r+=+31.667
This is the speed of the slower vehicle
in km/hr
31.667km/hr x 1%2F3600hr/sec x 1000 m/km
31.667+%2A+%281%2F3600%29+%2A+1000+=+8.796 m/s
The slower car is going 8.796 m/sec
check answer:
2r+=+17.593 m/s
190+%2A+1000+=+%2817.593+%2B+8.796%29%2A2%2A3600
190000+=+26.389+%2A+7200
190000+=+189997.867
Close enough