Question 206716: John travels by train to go home and arrives at the railway station every day at 17h00. His wife travels by car to pick him up at the station and arrives at the station at precisely 17h00. One day John took an earlier train and arrived at the station at 16h00 and was unable to phone his wife. He then started walking home hoping to meet his wife who would be on her way to pick him up. She did pick him up and they arrived home 12 min earlier than normal.
1) Assuming the wife travels at 60km per hour, how far did John walk?
2) How far is their home from the station?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! John travels by train to go home and arrives at the railway station every day at 17h00. His wife travels by car to pick him up at the station and arrives at the station at precisely 17h00. One day John took an earlier train and arrived at the station at 16h00 and was unable to phone his wife. He then started walking home hoping to meet his wife who would be on her way to pick him up. She did pick him up and they arrived home 12 min earlier than normal.
:
1) Assuming the wife travels at 60km per hour, how far did John walk?
:
Since him walking, knocked 12 min off the normal round trip time, we can say:
How far will she have driven in 12 min at 60 km/hr (12 min = .2 hr)?
.2 * 60 = 12 km
Since he was walking toward her, John walked half that: 6 km
:
:
2) How far is their home from the station?
I'm not sure how you can find that out.
I'm going to say at least 60 km; less, he could have called her, but she was
on her way when he arrived at the station at 1600.
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