SOLUTION: Science and medicine. Martina leaces home at 9 A.M., bicycling at a rate of 24mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up wi
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Question 20507: Science and medicine. Martina leaces home at 9 A.M., bicycling at a rate of 24mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? Answer by wuwei96815(245) (Show Source):
You can put this solution on YOUR website! This problem involves the equation distance = speed x time, or at least part of the equation.
The question is really asking at what point will the distance that Martina travels be equal to the distance that John travels?
Martina's distance = 24 mph x (t + 2) because she starts off two hours before John.
John's distance = 48mph x t
24mph x (t+2) = 48mph x t
24t + 48 = 48t
48 = 48t-24t
48 = 24t
2 = t
They will meet 2 hours after John starts. That will be at 1 P.M.
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