Question 204110: A hare is 30 meters in front of a hound., and he runs 3 meters while the hound runs 6 meters, how many meters must the hound run to catch the hare?
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! let n= intervals, periods of time
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6n = 30 +3n,,,,,hound runs 6 / interval,,hare runs 3/ interval but has 30 head start
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3n =30
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n=10
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therefore hound runs,,,10*6=60
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hare runs 10*3 = 30,,,plus head start of 30 = 60
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