SOLUTION: Golden painting. An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width? See the previou

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Question 202325This question is from textbook Elementary and Intermediate Algebra
: Golden painting. An artist wants her painting to be in the
shape of a golden rectangle. If the length of the painting is
36 inches, then what should be the width? See the previous
exercise. This question is from textbook Elementary and Intermediate Algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Golden painting. An artist wants her painting to be in the
shape of a golden rectangle. If the length of the painting is
36 inches, then what should be the width?
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width/length = 1/1.618
width = 36/1.618 = 22.25
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or, depending on which dimension larger,
width/length = 1.618
width = 36*1.618 = 58.248
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Cheers,
Stan H.