SOLUTION: Avoiding a collision. A car is traveling on a road that
is perpendicular to a railroad track. When the car is
30 meters from the crossing, the car’s new collision
detector warns
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-> SOLUTION: Avoiding a collision. A car is traveling on a road that
is perpendicular to a railroad track. When the car is
30 meters from the crossing, the car’s new collision
detector warns
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Question 200494This question is from textbook Elementary and Intermediate Algebra
: Avoiding a collision. A car is traveling on a road that
is perpendicular to a railroad track. When the car is
30 meters from the crossing, the car’s new collision
detector warns the driver that there is a train 50 meters
from the car and heading toward the same crossing. How
far is the train from the crossing? This question is from textbook Elementary and Intermediate Algebra
You can put this solution on YOUR website! Avoiding a collision. A car is traveling on a road that
is perpendicular to a railroad track. When the car is
30 meters from the crossing, the car’s new collision
detector warns the driver that there is a train 50 meters
from the car and heading toward the same crossing. How
far is the train from the crossing?
.
Applying Pythagorean theorem:
Let x = train's distance from crossing
then
x^2 + 30^2 = 50^2
x^2 = 50^2 - 30^2
x^2 = 2500 - 900
x^2 = 1600
x =
x = 40 meters
