SOLUTION: A certain aircraft can fly 1330 miles with the wind in 5 hours and travel the same distance against the wind in 7 hours. What is the speed of the wind?

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Question 183571: A certain aircraft can fly 1330 miles with the wind in 5 hours and travel the same distance against the wind in 7 hours. What is the speed of the wind?
Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
D=RT
R=D/T
R=1330/5
R=266 MPH WITH THE WIND.
R=1330/7
R=190 MPH AGAINST THE WIND
(266-190)/2=76/2=38 MPH IS THE WIND SPEED.
pROOF:
266-38=228 MPH FOR THE PLAN'S SPEED IN STILL AIR.
190+38=228 DITTO.

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A certain aircraft can fly 1330 miles with the wind in 5 hours and travel the same distance against the wind in 7 hours. What is the speed of the wind?
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Downwind DATA:
distance = 1330 ; time = 5 hrs ; rate = d/t = 1330/5 = 266 mph
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Upwind DATA:
distance = 1330 ; time = 7 hrs ; rate = d/t = 1330/7 = 190 mph
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Equations:
p + w = 266
P - w = 190
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Subtract 2nd equ. from 1st to get:
2w = 76
w = 38 mph (speed of the wind)
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Cheers,
Stan H.