SOLUTION: A train leaves Chicago going west. A second train leaves Chicago going east an hour earlier. The train going west travels at 51 mph while the train going east travels 87mph. How lo

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Question 179245: A train leaves Chicago going west. A second train leaves Chicago going east an hour earlier. The train going west travels at 51 mph while the train going east travels 87mph. How long the train headed west leaves are the trains 439 miles apart.
Found 2 solutions by josmiceli, ankor@dixie-net.com:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Set up 2 equations
For the west-bound train:
(1) d%5Bw%5D+=+r%5Bw%5D%2At%5Bwe%5D
For the East-bound train:
(2) d%5Be%5D+=+r%5Be%5D%2At%5Be%5D
given:
r%5Bw%5D+=+51mi/hr
r%5Be%5D+=+87mi/hr
d%5Bw%5D+%2B+d%5Be%5D+=+439mi
d%5Bw%5D+=+439+-+d%5Be%5D
t%5Be%5D+=+t%5Bw%5D+%2B+1hrs
------------------------
(1) d%5Bw%5D+=+r%5Bw%5D%2At%5Bw%5D
d%5Bw%5D+=+51%2At%5Bw%5D
439+-+d%5Be%5D+=+51t%5Bw%5D
(3)d%5Be%5D+=+-51t%5Bw%5D+%2B+439
------------------------
(2) d%5Be%5D+=+r%5Be%5D%2At%5Be%5D
d%5Be%5D+=+87%2A%28t%5Bw%5D+%2B+1%29
(4)d%5Be%5D+=+87t%5Bw%5D+%2B+87
Since (3) and (4) are both equal to d%5De%5D,
set them equal to eachother
-51t%5Bw%5D+%2B+439+=+87t%5Bw%5D+%2B+87
138t%5Bw%5D+=+439+-+87
138t%5Bw%5D+=+352
t%5Bw%5D+=+2.55hr
and
t%5Be%5D+=+t%5Bw%5D+%2B+1hrs
t%5Be%5D+=+3.55hrs
The trains are 439 mi apart 2.55 hrs after the westbound train leaves
check:
d%5Bw%5D+=+51%2At%5Bw%5D
d%5Bw%5D+=+51%2A2.55
d%5Bw%5D+=+130.1mi
and
d%5Be%5D+=+87t%5Be%5D
d%5Be%5D+=+87%2A3.55
d%5Be%5D+=+308.85
and
d%5Bw%5D+%2B+d%5Be%5D+=+439mi
130.1+%2B+308.85+=+439
438.95+=+439 close enough

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A train leaves Chicago going west. A second train leaves Chicago going east an
hour earlier. The train going west travels at 51 mph while the train going east
travels 87 mph. How long the train headed west leaves are the trains 439 miles apart.
;
Let t = travel time of the westbound train
then
(t+1) = travel time of the eastbound train
:
Write a distance equation: dist = speed * time
:
East dist + west dist = 439
87(t+1) + 51t = 439
87t + 87 + 51t = 439
87t + 51t = 439 - 87
138t = 352
t = 352%2F138
t = 2.55 hrs they will be 439 miles apart (from the time the westbound train leaves)
;
:
Check solution:
2.55*51 = 130
3.55*87 = 309 (travel time 1 hr longer)
---------------
total d = 439 mi