SOLUTION: question 1) A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current. question 2) E

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Question 166073: question 1) A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current.
question 2) Erin's age is 3 times Warren's. In 4 years she will be twice as old as he will be. How old is each now.
Found 2 solutions by midwood_trail, Mathtut:
Answer by midwood_trail(310) About Me  (Show Source):
You can put this solution on YOUR website!
I will do question only.
(2) Erin's age is 3 times Warren's. In 4 years she will be twice as old as he will be. How old is each now.
I will do question (2) first.
Warren's age now is x.
Erin's age now is 3x.
In 4 years, they both will be 4 years older, right?
3x + 4 = Erin's age 4 years form now.
x + 4 = Warren's age 4 years from now.
3x + 4 = 2(x + 4)
3x + 4 = 2x + 8
3x - 2x = 8 - 4
x = 4
Warren is 4 years old now.
Erin is 3(4) years old now or 12 years old.
Did you follow?
For question (1), you are dealing with two equations in two variables.



Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
so the speed of the sailboat downstream is 20%2F3=6.66mph
the speed of the sailboat upstream is 20%2F4=5+++mph
the speed of the stream is %286.66-5%29%2F2=+.83mph
speed of sailboat in still water is 6.66-.833=5.83mph