SOLUTION: I appreciate your help with this word problem:
A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hour
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A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hour
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Question 129113This question is from textbook Introductory Algebra
: I appreciate your help with this word problem:
A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hour less time. How far apart are the towns?
Thanks!!! This question is from textbook Introductory Algebra
You can put this solution on YOUR website! A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hour less time. How far apart are the towns?
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Car DATA:
Rate = 32 mph ; distance = x miles ; time = d/r = x/32 hrs
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New Car DATA:
Rate = 36 mph ; distance = x miles ; time = d/r = x/36 hrs
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EQUATIOn:
old time - new time = 1/2 hr
x/32 - x/36 = 1/2
(36x-32x)/32*36 = 1/2
4x = (32*36)/2
x = 8*18
x = 144 miles (distance between the towns)
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Cheers,
Stan H.
You can put this solution on YOUR website! EQUATIOn:
old time - new time = 1/2 hr
x/32 - x/36 = 1/2
(36x-32x)/32*36 = 1/2
4x = (32*36)/2
x = 8*18
x = 144 miles (distance between the towns
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