Question 1204938: a rocket is moving vertically upward at a speed of 245 meters per second when its fuel runs out. how much farther will it start to travel upward before starting fall back to the ground.
Answer by ikleyn(52776)   (Show Source):
You can put this solution on YOUR website! .
a rocket is moving vertically upward at a speed of 245 meters per second
when its fuel runs out. how much farther will it start to travel upward
before starting fall back to the ground.
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Write equation relevant to this problem
h(t) = -10*t^2 + 245t +  .
Here h(t) is the current height, t is the time, counted from the moment,
when the fuel stopped running; is the height, where the fuel stop running.
From this equation, find the time  for the maximum height
= "  " =  =  = 12.25 seconds.
Now
"how much farther" = -10*12.25^2 + 245*12.25 = 1500.625 meters. ANSWER
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In this site, I prepared the lessons that cover the entire subject
- Introductory lesson on a projectile thrown-shot-launched vertically up
- Problem on a projectile moving vertically up and down
- Problem on an arrow shot vertically upward
- Problem on a ball thrown vertically up from the top of a tower
- Problem on a toy rocket launched vertically up from a tall platform
- A flare is launched from a life raft vertically up
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Read them attentively and learn how to formulate and how to solve this type of problems once and for all.
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