SOLUTION: Jack leaves his home, traveling north at an average rate of 55 miles per hour. Five hours later, his wife, Frances, leaves home and takes the same route traveling at an average rat

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Question 1197866: Jack leaves his home, traveling north at an average rate of 55 miles per hour. Five hours later, his wife, Frances, leaves home and takes the same route traveling at an average rate of 80 miles per hour. How long will it take Frances to catch Jack?
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi D =rt Both Jack and Frances traveling equal distances: Question states (55mph)t = (80mph)(t-5) 400 = 25t 400/25 = t = 16hr, Jack's time Frances time = 11hr checking: 55mph*16h = 80mph*11h = 880mi checks Wish You the Best in your Studies.

Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website!

SPEED TIME DIST. JACK 55 x+5 d FRANCES 80 x d