SOLUTION: Please help me solve this :
Roy leaves for work at 7 A.M. traveling 40kph. His sister Susan finds that he
has forgotten his briefcase, so she leaves at 7:05 A.M. chasing him at 5
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Roy leaves for work at 7 A.M. traveling 40kph. His sister Susan finds that he
has forgotten his briefcase, so she leaves at 7:05 A.M. chasing him at 5
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Question 1194492: Please help me solve this :
Roy leaves for work at 7 A.M. traveling 40kph. His sister Susan finds that he
has forgotten his briefcase, so she leaves at 7:05 A.M. chasing him at 50kph.
At what time will Susan catch up with Roy?
Please Include Represent, Relate, Equate, Solve and Prove. Thank you very much! Answer by josgarithmetic(39616) (Show Source):
You can put this solution on YOUR website! Five minutes later is of an hour. Roy traveled kilometers and so Susan is that much distance from him once she begins travel.
Her approach rate is 10 kph; enough for you to understand and hopefully finish.
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