SOLUTION: A bicyclist bikes the 24 mi to a city averaging a certain speed. The return trip is made at a speed that is 4 mph slower. The total time for the round trip is 5 hr. Find the​ b

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A bicyclist bikes the 24 mi to a city averaging a certain speed. The return trip is made at a speed that is 4 mph slower. The total time for the round trip is 5 hr. Find the​ b      Log On

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Question 1194434: A bicyclist bikes the 24 mi to a city averaging a certain speed. The return trip is made at a speed that is 4 mph slower. The total time for the round trip is 5 hr. Find the​ bicyclist's average speed on each part of the trip.
Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


Get some good mental exercise by solving the problem informally.

The distance is a whole number, the total time is a whole number, and the difference in speeds is a whole number. So the two speeds are almost certain to be whole numbers.

So look for two speeds that are whole numbers of miles per hour that differ by 4 and for which the total time going 24 miles and returning is 5 hours. A little trial and error should quickly find speeds of 12 and 8 mph: 24%2F12%2B24%2F8+=+2%2B3+=+5.

ANSWERS: 12mph going; 8mph returning

With formal algebra....

Let x be his speed going
Then x-4 is his speed returning

The total time for 24 miles each way is 5 hours:

24%2Fx%2B24%2F%28x-4%29=5

Multiply by the common denominator, x(x-4):

24%28x-4%29%2B24%28x%29=5%28x%29%28x-4%29
24x-96%2B24x=5x%5E2-20x
5x%5E2-68x%2B96=0
%28x-12%29%285x-8%29=0

x=12 or x=8%2F5

x=8/5 makes no sense, since it would make the return trip at a negative speed; so x=12.

ANSWERS:
going: x=12mph
returning: x-4=8mph