Question 1183135: An object is launched over level ground at 35 degrees above the horizontal with an initial speed of 52 m/s. What is the time of flight? Answer by ikleyn(52775) (Show Source):
You can put this solution on YOUR website! .
An object is launched over level ground at 35 degrees above the horizontal
with an initial speed of 52 m/s. What is the time of flight?
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Calculate vertical component of the speed = 52*sin(35°) meters per second.
Then the time flying up to the highest point is t = seconds, where g is the gravity acceleration.
The time falling dawn is the same value.
THREFORE, the total time of flight is 2t = .
All calculations are ELEMENTARY, so I leave them to you.
