SOLUTION: A 0.5 kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 8.0 N for a distance of 4.0 m how much kinetic energy does the block gain

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Question 1182591: A 0.5 kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 8.0 N for a distance of 4.0 m how much kinetic energy does the block gain
Answer by mananth(16946) About Me  (Show Source):
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Change in Kinetic energy = Work done on object
Work done = F * D
=8.8N *4m
= 35.2 J
Therefore, block gains
35.2 Joule of Kinetic energy.