SOLUTION: An Arctic tractor drags a 45 ton (that's metric ton 1 ton equals 1000 kg) across the snow which has a friction coefficient of 0.075 a distance of 4500 kilometers how much work did
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Question 1182529: An Arctic tractor drags a 45 ton (that's metric ton 1 ton equals 1000 kg) across the snow which has a friction coefficient of 0.075 a distance of 4500 kilometers how much work did the tractor do Answer by ikleyn(52756) (Show Source):
Convert all given data in kilograms and meters
45 tons = 45000 kilograms (kg);
4500 kilometers = 4500000 meters (m).
The friction force is the product of the weight by the friction coefficient k.
The weight is W = 45000 kilograms * 10 m/s^2 = 450000 newtons.
The friction force is F = k*W = 0.075*450000 = 33750 newtons.
The work done is the product of the friction force by the distance
A = F*d = 33750 * 4500000 = 1.51875E+11 joules = 1.51875E+8 kilo-joules. ANSWER
