SOLUTION: Peter travels from his place to his uncle house a distance of 30km.He cycles for two thirds of the journey before walking for the rest of the journey. If his cycling speed is 10km/

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Question 1176010: Peter travels from his place to his uncle house a distance of 30km.He cycles for two thirds of the journey before walking for the rest of the journey. If his cycling speed is 10km/hr more than the walking speed and the whole journey took him 3hrs 20 minutes, calculate his cycling speed.
Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
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Peter travels from his place to his uncle house a distance of 30km.He cycles for two thirds of the journey
before walking for the rest of the journey. If his cycling speed is 10km/hr more than the walking speed
and the whole journey took him 3hrs 20 minutes, calculate his cycling speed.
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Let x be his cycling speed in km/h;  then his walking speed was (x-10) km/h.


He cycled 20 km at the speed x km/h --- hence, he spent  20%2Fx  hours for this part of the journey.


He walked 10 km at the speed (x-10) km/h --- hence, he spent  10%2F%28x-10%29  hours for this part of the journey.


The total time was  3 hours 20 minutes = 3 1%2F3 hours = 10%2F3 hours.


It gives you this "time equation"


    20%2Fx + 10%2F%28x-10%29 = 10%2F3.     (1)


To solve it, multiply both sides by 3


    60%2Fx + 30%2F%28x-10%29 = 10.            (2)


At this point, you just can easily guess the solution MENTALLY:  it is x= 15 km/h.


Alternatively, you may reduce equation (1) or (2) to the standard form quadratic equation and solve it formally.


ANSWER.  His cycling speed is 15 km/h.


CHECK.  I will check equation (1) :  20%2F15+%2B+10%2F5 = 1 1%2F3 + 2 = 3 + 1%2F3  hours.    ! Correct !

Solved.