SOLUTION: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 15mph slower than the other. If the two jets are 6730 miles apart after 5 hours, what

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Question 1167303: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 15mph slower than the other. If the two jets are 6730 miles apart after 5 hours, what is the rate of each jet?
Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let r be the rate of the slower jet;  then the rate of the faster jet is (r+15) mph.


The total separating distance is

    5r + 5*(r+15),


and it is equal to 6730.  So your base equation is

    5r + 5*(r+15) = 6730.


Simplify and find r

    5r + 5r + 75 = 6730

    10r          = 6730 - 75 = 6655

      r                      = 665.5.


ANSWER.  The rate of the slower jet is  665.5 mph.

         The rate of the faster jet is  665.5 + 15 = 680.5 mph.


CHECK.  5*665.5 + 5*680.5 = 6730  separating distance in 5 hours.   ! Correct !

Solved.

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