SOLUTION: Sam drives from City A to City B, and Richard drives from City B to City A on the same road. When they meet, Sam has driven 120 km. They continue to drive to their own destination.

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Sam drives from City A to City B, and Richard drives from City B to City A on the same road. When they meet, Sam has driven 120 km. They continue to drive to their own destination.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1163673: Sam drives from City A to City B, and Richard drives from City B to City A on the same road. When they meet, Sam has driven 120 km. They continue to drive to their own destination. When they arrive at their destination, they turn around and continue to drive. When they meet the second time, the place is 1/5 of the distance between the two cities away from City B. What is the distance between the two cities?
Answer by ikleyn(52772) About Me  (Show Source):
You can put this solution on YOUR website!
.
Sam drives from City A to City B, and Richard drives from City B to City A on the same road. When they meet, Sam has driven 120 km.
They continue to drive to their own destination. When they arrive at their destination, they turn around and continue to drive.
When they meet the second time, the place is 1/5 of the distance between the two cities away from City B.
What is the distance between the two cities?

Solution

The scheme of placing points is shown in the Figure below.


    +--------------------------------|-----------|--------------+

    A                                M           F              B 


Points A and B are cities;  point M is the 1st meeting point;  point F is the 2-nd meeting point.

So, AM = 120 kilometers.

Let x be the distance from the 1st meeting point to B.

Thus the total distance is 120+x kilometers.



The times driving from the starting points to the 1st meeting pojnt are the same

    120%2FV%5BS%5D = x%2FV%5BR%5D,     (1)

where  V%5BS%5D  and  V%5BR%5D are the rates of Sam and Richard, respective.



It is our first equation, which I want to rewrite in this form as the ratio of their rates

    V%5BS%5D%2FV%5BR%5D = 120%2Fx.     (2)



The distance Sam     drove from the 1st meeting point to the second meeting point was  x+%2B+%281%2F5%29%2A%28120%2Bx%29 km.

The time Sam     spent covering this distance was  T%5BS%5D = %28x+%2B+%281%2F5%29%2A%28120%2Bx%29%29%2FV%5BS%5D  hours.



The distance Richard drove from the 1st meeting point to the second meeting point was  120+%2B+%284%2F5%29%2A%28120%2Bx%29 km.

The time Richard spent covering this distance was  T%5BR%5D = %28120+%2B+%284%2F5%29%2A%28120%2Bx%29%29%2FV%5BR%5D  hours.


The times  T%5BS%5D  and  T%5BR%5D are the same;  it leads to equation

   
    %28x+%2B+%281%2F5%29%2A%28120%2Bx%29%29%2F%28120+%2B+%284%2F5%29%2A%28120%2Bx%29%29 = V%5BS%5D%2FV%5BR%5D.



In the right side, replace  V%5BS%5D%2FV%5BR%5D  by  120%2Fx,  based on (2).  You will get then

    %28x+%2B+%281%2F5%29%2A%28120%2Bx%29%29%2F%28120+%2B+%284%2F5%29%2A%28120%2Bx%29%29 = 120%2Fx.



Simplify it step by step

    %286x+%2B+120%29%2F%281080+%2B+4x%29 = 120%2Fx

    %283x+%2B+60%29%2F%28540+%2B+2x%29 = 120%2Fx

    x*(3x + 60) = 120*(540+2x)

    3x^2 + 60x = 120*540 + 240x 

    3x^2 - 180x - 120*540 = 0

      x^2 - 60x - 21600 = 0    

      (x+120)*(x-180) = 0


Of the two roots,  -120 and 180,  only positive 180  makes sense.


So, the distance x is 180 kilometers, and the total distance from A to B is  120+180 = 300 kilometers.     ANSWER

Solved.

---------------

Surely, this problem is two levels higher than a regular Math/Physics problem in any high school.

It is, actually, an Olympiad level problem in Physics.

Could you tell me please where is it from, from which source ?


Do not forget to post your "THANKS" to me for my teaching.