Question 1163588: Albert and Bob start at the same point to run clockwise around a circular track with 600 meters, and they meet every 12 minutes. If they start at the same point to run opposite direction, they meet every 4 minutes. How many minutes do Albert and Bob need to run one lap respectively?
Answer by ikleyn(52756) (Show Source):
You can put this solution on YOUR website! .
When they run in one direction, they will meet for the first time when the faster runner will cover
the distance in one circumference longer that the slower runner.
So, let assume that "u" is the rate running of Albert and "v" is the rate of Bob,
and let assume that Albert is faster than Bob.
Then the criterion :first time meet after start" is this equation
u*t - v*t = 600 meters, or
(u - v)*12 = 600, which implies
u - v = 600/12 = 50 meter per minute.
When they run in opposite direction, the criterion to meet is
u*t + v*t = 600 meters, or
(u + v)*4 = 600, which implies
u + v = 600/4 = 150 meters per second.
Thus you have these two equations to find unknowns "u" and "v"
u + v = 150 (1)
u - v = 50 (2)
To solve the system, add the equations. You will get
2u = 150 + 50 = 200, u = 200/2 = 100 m/sec.
Then from equation (1) you find v = 150 - u = 150 - 100 = 50 m/sec.
Thus the rates "u" and "v" are just found.
Then you make the last step to get the answer:
time for Albert = 600/100 = 6 minuter per lap, and
time for Bob = 600/50 = 12 minuter per lap.
Solved.
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