Question 1157210: a private plane traveled from seattle to a rugged wilderness at an average of 132 mph. On the return trip, the average speed was 231 mph. If the total traveling time was 6 hours, how far is Seattle from the wideness?
Found 4 solutions by josgarithmetic, josmiceli, greenestamps, MathTherapy:
Answer by josgarithmetic(39630)   (Show Source):
Answer by josmiceli(19441)  (Show Source):
Answer by greenestamps(13215)  (Show Source):
You can put this solution on YOUR website!
The distances are the same, and the ratio of the speeds is 132:231 = 4:7. That means the ratio of times is 7:4.
So 4/11 of the 6 hours was spent at the higher speed. The distance is then
Or of course you could calculate the distance as 7/11 of the total 6 hours at 132mph.
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website!
a private plane traveled from seattle to a rugged wilderness at an average of 132 mph. On the return trip, the average speed was 231 mph. If the total traveling time was 6 hours, how far is Seattle from the wideness?
Let distance be D
Then we get the following TIME equation: 
7D + 4D = 5,544 ------ Multiplying by LCD, 924
11D = 5,544
Distance, or 
NOTHING else to this!!
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