SOLUTION: Arnold sets out for a hike. After walking for some time, he discovers that he left his lunch. A passing passenger bus takes him back home at 40kph. When he gets home he finds ou

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Arnold sets out for a hike. After walking for some time, he discovers that he left his lunch. A passing passenger bus takes him back home at 40kph. When he gets home he finds ou      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1144894: Arnold sets out for a hike. After walking for some time, he discovers that he left his lunch. A passing passenger bus takes him back home at 40kph. When he gets home he finds out that he was gone for 1 hour. How far did he walk if his rate was 5 kph?

Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let "d" be the unknown distance.


Then you have this "time" equation


    d%2F5 + d%2F40 = 1 hour.


To solve it, multiply both sides by 40. You will get


    8d + d = 40,

    9d = 40

     d = 40%2F9 kilometers.    ANSWER


==================

I am solving, printing and posting faster (and in more correct way) than you copy, paste and submit (!)

I won (!)