SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t      Log On

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Question 1130021: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1 hour 12 minutes. What is his speed in still air, and how fast is the wind blowing?
His speed equal-
wind speed equals-

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+s+ = plane's speed in still air
+w+ = wind speed
------------------------------------
Going against the wind:
(1) +180+=+%28+s+-+w+%29%2A2+
Going with the wind:
(2) +180+=+%28+s+%2B+w+%29%2A%28+1+%2B+12%2F60+%29+
------------------------------------------
(2) +180+=+%28+s+%2B+w+%29%2A1.2+
(2) +s+%2B+w+=+150+
and
(1) +s+-+w+=+90+
Add the equations
+2s+=+240+
+s+=+120+
and
(1) +120+-+w+=+90+
(1) +x+=+30+
Plane's speed in still air is 120 mi/hr
Wind speed is 30 mi/hr
---------------------------------------
checK
(1) +180+=+%28+120+-+30+%29%2A2+
(1) +180+=+180+
OK
(2) +180+=+%28+120+%2B+30+%29%2A1.2+
(2) +180+=+150%2A1.2+
(2) +180+=+180+
OK