SOLUTION: At a concession​ stand, seven hot dog left parenthesis s right parenthesis and four hamburger left parenthesis s right parenthesis cost ​$16.00​; four hot dog lef

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Question 1129051: At a concession​ stand, seven hot dog left parenthesis s right parenthesis and four hamburger left parenthesis s right parenthesis cost ​$16.00​; four hot dog left parenthesis s right parenthesis and seven hamburger left parenthesis s right parenthesis cost ​$19.75. Find the cost of one hot dog and the cost of one hamburger.
Answer by greenestamps(13198) About Me  (Show Source):
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Let x be the cost of a hot dog and y be the cost of a hamburger. Then the given information says

7x%2B4y+=+16.00
4x%2B7y+=+19.75

Typically, you would solve the pair of equations using elimination, to find the values of x and y.

But observe that the question does NOT ask you to find the cost of each hot dog and each hamburger; it only asks you to find the cost of one of each.

And a quick look at the equations for the problem should show a quick way to the answer: adding the two equations gives the cost of 11 hot dogs and 11 hamburgers; then dividing by 11 gives the cost of one of each. So

11x%2B11y+=+35.75
x%2By+=+3.25

ANSWER: The cost of one hot dog and one hamburger is $3.25.