SOLUTION: Paul made a trip to the recycling plant and back. The trip there took 4 hours and the trip back took 6 hours. He averaged 25 km/h faster on the trip there than on the return trip.

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Question 1122401: Paul made a trip to the recycling plant and back. The trip there took 4 hours and the trip back took 6 hours. He averaged 25 km/h faster on the trip there than on the return trip. What was paul's average speed on the outbound trip?
Answer by josgarithmetic(39616) About Me  (Show Source):
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Paul made a trip to the recycling plant and back. The trip there took 4 hours and the trip back took 6 hours. He averaged 25 km/h faster on the trip there than on the return trip. What was paul's average speed on the outbound trip?
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               SPEED        TIME      DISTANCE
GOING           r            4           d
RETURN         r-25          6           d


Same distance d each way.
4r=6%28r-25%29
Solve this.