SOLUTION: Mary weighs 45 pounds and sits six feet from the fulcrum of a Seesaw. If Bob who weighs 60 pounds wants to keep the seasaw balanced, how far from the fulcrum must he sit?

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Question 1114758: Mary weighs 45 pounds and sits six feet from the fulcrum of a Seesaw. If Bob who weighs 60 pounds wants to keep the seasaw balanced, how far from the fulcrum must he sit?
Answer by ikleyn(52795) About Me  (Show Source):
You can put this solution on YOUR website!
.
The equilibrium condition on a seesaw is


W%5B1%5D%2Ad%5B1%5D = W%5B2%5D%2Ad%5B2%5D,


where W is the weight,  d is the distance from the fulcrum and "1" and "2" are indexes.


In your case  45*6 = 60*x,   which gives


x = %2845%2A6%29%2F60 = 4.5 ft.

See the lesson
    - Using proportions to solve word problems in Physics
in this site.