SOLUTION: what is the reference angle for a 960 degree angle? show all work please

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Question 1112429: what is the reference angle for a 960 degree angle? show all work please
Found 2 solutions by Theo, KMST:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
first you find the equivalent positive angle between 0 and 360 degrees.

just subtract 360 from 960 until you get there.

960 - 360 = 600 - 360 = 240

the equivalent angle between 0 and 360 degrees is 240 degrees.

that angle is in the third quadrant.

the reference angle for an angle in the third quadrant is that angle minus 180 degrees.

240 - 180 = 60 degrees.

that's your reference angle.

you can use your calculator to confirm.

if the angle is the reference angle, then the sine and cosine and tangent of the angle will be the same as the sine and cosine and tangent of the reference angle except for the sign.

the sine in the third quadrant is negative.
the cosine in the third quadrant is negative.
the tangent in the third quadrant is positive.

using my calculator, i get:

sin(60) = + .8660254038
cos(60) = + .5
tan(60) = + 1.732050808

sin(240) = - .8660254038
cos(240) = - .5
tan(240) = + 1.732050808

the trig functions are the same except for the sign, therefore 60 degrees is the reference angle for 240 degrees.

to confirm that 240 degrees is equivalent to 960 degrees, i got the trig functions for 960 degrees, using my calculator.

sin(960) = - .8660254038
cos(960) = - .5
tan(960) = + 1.732050808

that's identical to the trig functions for 240 degrees, therefore 960 degrees and 240 degrees are equivalent.


Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Here is what a 960%5Eo looks like,
It's 2 turns and 240%5Eo (all counterclockwise, of course).
When you divide 960%5Eo by 360%5Eo the quotient is 2 and the remainder is 240%5Eo .
You do not need to divide (unless the angle measure is huge).
You can keep subtracting 360%5Eo (one turn) until you get less than one turn.
You can write that as
960%5Eo-360%5Eo-360%5Eo=240%5Eo , or 960%5Eo-2%28360%5Eo%29=240%5Eo , or 960%5Eo-720%5Eo=240%5Eo .
Now you have to work with 240%5Eo , the co-terminal angle of 960%5Eo .
An angle measuring 240%5Eo is in the third quadrant,
where all the angles between 180%5Eo and 270%5Eo are located.
You can write that as
180%5Eo%3C240%5Eo%3C270%5Eo .
The reference angle is a symmetrical angle in quadrant I, and that angle has the same absolute value for all trigonometric functions.
For quadrant III, it is easy, you just subtract half a turn<, 180%5Eo ,
and that gives you the angle with the opposite ray for a terminal side:
The reference angle is 240%5Eo-180%5Eo=highlight%2860%5Eo%29 .