SOLUTION: Against the wind a small plane flew 280 miles in 1 hour and 10 minutes. The return trip took only nothing50 minutes. What was the speed of the​ wind? What was the spe

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Question 1102966: Against the wind a small plane flew 280 miles in 1 hour and 10 minutes.

The return trip took only nothing50 minutes.

What was the speed of the​ wind? What was the speed of the plane in still​ air?

Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let u = the speed of the plane at no wind, in miles per hour.

    v = speed of the wind.


Then the speed "with the wind" is (u+v) mph,

while the speed "against the wind" is (u-v) mph.


Then your equations ("the speed equations") are

280%2F%28%287%2F6%29%29 = u - v,   (speed = Dist%2FTime;  7%2F6 = 7%2F6 hours = 1 hour 10 minutes)

280%2F%28%285%2F6%29%29 = u + v.   (                          5%2F6 = 5%2F6 hours = 50 minutes).


Simplify the equations

u - v = %28280%2A6%29%2F7 = 240,     (1)
u + v = %28280%2A6%29%2F5 = 336.     (2)


Add the equation (1) and (2) to get

2u = 240 + 336 = 576  ====>  u = 576%2F2 = 288.

Then from  (2),  v = 336 - 288 = 48.


Answer.  The aircraft speed at no wind is 288 mph.  Speed of the wind is 48 mph.


--------------
Please formulate your problems ACCURATELY, using appropriate terminology.

Thanks.


Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
Speed against wind, 280%2F%287%2F6%29=280%286%2F7%29=240

Speed with wind, 280%2F%285%2F6%29=280%286%2F5%29=336

r, speed if no wind
w, speed of wind

system%28r-w=240%2Cr%2Bw=336%29
2r=240%2B336
highlight%28r=288%29
-
w=%28336-240%29%2F2
highlight%28w=48%29