SOLUTION: Hi please help me im clueless .... thank you soo muchh First is this you have to do it with a chart inside wil say ratextime=distance and the equation inside with the variabl

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Question 110056This question is from textbook
: Hi please help me im clueless .... thank you soo muchh
First is this you have to do it with a chart
inside wil say ratextime=distance and the equation inside with the variables.
ok here is the problem
It takes plane 40min longer to fly from Boston to Los Angeles at 52 mi/h than it does to return at 600mi/h. how far apart are the cities.?
THE SECOND IS THIS
It took Cindy 2h to bike from Abbott to Benson at a constant speed. The return trip took only 1.5h because she increased her speed by 6km/h. How far apart are Abbott and Benson?
thank you sooo muchh
i appreciate it i have a test on this tomorrow
 This question is from textbook

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
It takes plane 40min longer to fly from Boston to Los Angeles at 520 mi/h than it does to return at 600mi/h. how far apart are the cities.?
------------------
To LA DATA:
Time = x+(2/3) hr ; rate = 520 mph ; distance = rt = 520[x+(2/3)]=520x+700 miles
----------------
To Boston DATA:
Time = x hr ; rate = 600 mph ; distance = 600x miles
----------------
EQUATION:
distance = distance
520x+700 = 600x
80x = 700
x = 8.75 hrs (time from LA to Boston)
------------
600x = 5250 miles (distance between the cities)
=====================
Note: I changed your 52 mph rate to 520 mph
======================
---------------------
THE SECOND IS THIS
It took Cindy 2h to bike from Abbott to Benson at a constant speed. The return trip took only 1.5h because she increased her speed by 6km/h. How far apart are Abbott and Benson?
thank you sooo much
-----------
To Benson DATA:
Time = 2 hrs ; rate = x kph ; distance = rt = 2x km
----------------
To Abbott DATA:
Time = 1.5 hrs ; rate = (x+6) kph ; distance = rt = (3/2)(x+6) km
---------------
EQUATION:
distance = distance
2x = (3/2)x+9
(1/2)x = 9
x = 18 kph (rate from Abbott to Benson)
2x=36 km (distance between Abbott and Benson)
======================
Cheers,
Stan H.