SOLUTION: A very large number of balls are thrown vertically upwards in quick succession in such a way that the next ballis thrown when the previous one is at maximum height. If maximum heig

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Question 1090436: A very large number of balls are thrown vertically upwards in quick succession in such a way that the next ballis thrown when the previous one is at maximum height. If maximum height is 5m, number of balls thrown per minute is ?
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
You have to give the function for height vs. time.

Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
All we need to know is the time for which the ball thrown vertically up reaches its maximum height of 5 m.


If you ask a physicist, he immediately will answer you: the same time which is needed for freely falling ball 
to fall down 5 m, and will write an equation for it:

%28gt%5E2%29%2F2 = 5.     (1)


For this problem, the physicist will take the gravity acceleration g equal to 10 m/s^2 (instead of the more precise 
value of 9.81 m/s^2), and then the equation (1) becomes

%2810%5Et%5E2%29%2F2 = 5,   or

t%5E2 = %285%2A2%29%2F10 = 1,


which implies t = 1 second for time.


So, the time interval between two successions is 1 seconds, and the number of balls thrown per minute is 60.


Answer.   The time interval between two successions is 1 seconds, and the number of balls thrown per minute is 60.

Solved.