Question 1063035: a body starts with intial velocity 30m/s and a retardation of4m/s square. find the distance travelled by the body in the 8th second Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! d(t) = ((-4*t^2)/2) + 30t
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d(8) = (-4(8^2)/2) + 30*8 = 112 meters
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The general form is
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s = v(i)*t + (1/2)*a*t^2, where s is distance, v(i) is initial velocity, a is acceleration and t is time
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