SOLUTION: A cat on seeing a dog 100m away turns around and start running away at 24 kmph.The dog spots him one minute later and start chasing the cat at a speed of 33kmph.After how much time

Question 1056102: A cat on seeing a dog 100m away turns around and start running away at 24 kmph.The dog spots him one minute later and start chasing the cat at a speed of 33kmph.After how much time,from the start of the cat's run,will the chase end?
Please explain with the help of diagram
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!

SPEED TIME DISTANCE CAT 24 t+(1/60) d DOG 33 t d+0.1

Time units all in hours and distance units all in kilometers.
Constant Travel Rate Rule, RT=D.
Answer by ikleyn(52835)   (Show Source): You can put this solution on YOUR website!
.
A cat on seeing a dog 100 m away turns around and start running away at 24 km/h. The dog spots him one minute later
and start chasing the cat at a speed of 33 km/h. After how much time,from the start of the cat's run,will the chase end?
~~~~~~~~~~~~~~~~~~~~~~~~~

The speed of the cat is 24 km/h, which is = 400 meters per minute. Therefore, the initial distance between the cat and the dog was 100 m + 400 m = 500 meters. (400 m was the distance the cat run away in one minute before the dog started chasing the cat) The distance between the dog and the cat is decreasing in 33-24 = 9 km per hour, which is = 150 meters per minute. Hence, the dog will catch the cat in = minutes = 3 minutes and 20 seconds after the dog starts, or in 4 minutes and 20 seconds after the cat start. I wish the cat to find the tall tree before the dog will catch him.

Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

A cat on seeing a dog 100m away turns around and start running away at 24 kmph.The dog spots him one minute later and start chasing the cat at a speed of 33kmph.After how much time,from the start of the cat's run,will the chase end?
Please explain with the help of diagram

I don't do diagrams. Sorry. You have to visualize it and draw your own diagram.
Let time the cat takes to get to the catch point be T
Then time dog takes to get to catch up point =
Since they�re travelling in km, then distance between the 2 is: .1 km (100 m)
We then get the following DISTANCE equation:

480T � 660T = - 11 - 2 -------- Multiplying by LCD, 20
- 180T = - 13
T, or time the chase ended (dog caught up), from the time the cat started running =
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