SOLUTION: Kent drives his Mazda 531 miles in the same time that it takes Dave to drive his Nissan 495 miles. If Kent averages 4 miles per hour faster than Dave, find their rates.

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Question 1055214: Kent drives his Mazda 531 miles in the same time that it takes Dave to drive his Nissan 495 miles. If Kent averages 4 miles per hour faster than Dave, find their rates.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
                  SPEED      TIME       DISTANCE
MAZDA,Kent         r+4        t          531
NISSAN,DAVE         r         t          495

RT=D basic rule.
The times, t, are equal.

Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.
Kent drives his Mazda 531 miles in the same time that it takes Dave to drive his Nissan 495 miles.
If Kent averages 4 miles per hour faster than Dave, find their rates.
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Your equation is

531%2F%28r%2B4%29 = 495%2Fr.


Right side is the time spent by Dave to drive 496 miles at the rate of r mph.
Left side is the time spent by Kent to drive 531 mile at the rate (r+4) mph.

To solve the equation, multiply both sides by r*(r+4) to get

531r = 495*(r+4).

Now simplify and solve for r.

Answer.  r = 55 mph (Dave).  r+4 = 59 mph (Kent).