SOLUTION: A train leaves San Diego at 1:00 PM. A second train leaves the same city in the same direction at 3:00 PM. The second train travels 30 mph faster than the first. If the second trai

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Question 1052741: A train leaves San Diego at 1:00 PM. A second train leaves the same city in the same direction at 3:00 PM. The second train travels 30 mph faster than the first. If the second train overtakes the first at 6:00 PM, what is the speed of each of the two trains?
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
A very typical catchup-travel type problem. Basic constant travel rate rule is RT=D. Time is best handled in quantities, and not as points on a time-line, but this is only to make handling easier values for analyzing and solving the problem.

Only a data table is presented here. You do the rest. 
                  SPEEDS           TIME           DISTANCE
FIRST             r                t+2             d
SECOND            r+30              t              d


Excuse me. I left something out.
highlight_green%28t%2B2=5%29.

Here is an adjustment to the data table, using according to the meaning of the time points in the description:
                  SPEEDS           TIME           DISTANCE
FIRST             r                 5              d
SECOND            r+30              3              d

NOW you can do the rest.